A question for those that can cipher.

submitted by Eatshitmotherfuckers from self.whatever

How can you write the number two thirds without using numbers between one and seven?

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newinsightfulfun

[–]AXXA👁⃤웃 2 insightful - 1 fun2 insightful - 0 fun3 insightful - 1 fun -  (3 children)

(9+9)/(9+9+9)

[–][deleted] 2 insightful - 1 fun2 insightful - 0 fun3 insightful - 1 fun -  (2 children)

My first guess was using binary but this is really cool.

[–]AXXA👁⃤웃 2 insightful - 1 fun2 insightful - 0 fun3 insightful - 1 fun -  (1 child)

Thanks. I originally came up with a more complicated solution but then realized this far more elegant solution. Any rational number can be represented using this pattern by varying the amount of nines. An even more general representation would be (X+X)/(X+X+X) where X does not equal zero. X doesn't even have to be a number. It could be (Apple + Apple)/(Apple + Apple + Apple).

[–][deleted] 2 insightful - 1 fun2 insightful - 0 fun3 insightful - 1 fun -  (0 children)

You seem quite invested into modern mysticism.

Keep on going, maybe you'll discover something thing. This kind of magic stays as fascinating as it ever was.

[–][deleted] 1 insightful - 1 fun1 insightful - 0 fun2 insightful - 1 fun -  (0 children)

cubic root(8) / square root (9). Ok I cheated writing the powers